IB HL

Meiosis, Genetics & Inheritance

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Topics Covered in This Guide

  • D2.1 Meiosis — chromosome behaviour in meiosis I and II, crossing over at chiasmata, independent assortment, genetic variation
  • D2.2 Inheritance — Mendel’s laws, monohybrid and dihybrid crosses, sex-linkage, codominance (ABO), incomplete dominance
  • D2.3 Gene Pools & Speciation — allele frequency, Hardy-Weinberg principle (qualitative), allopatric and sympatric speciation
  • MCQ Practice — styled like real IB Paper 1 questions
  • Exam Alerts — the exact traps that cost marks in D2 questions

Aligned to IB Biology 2025 syllabus — D2.1 Meiosis — D2.2 Inheritance — D2.3 Speciation


Jump to section: Meiosis · Inheritance Patterns · Gene Pools & Speciation · MCQ Practice · Exam Strategy


Section 1: Meiosis (D2.1)

Overview

Meiosis is a specialised form of cell division that produces four genetically unique haploid cells from one diploid parent cell. It occurs in the gonads (testes and ovaries in animals) and is the basis of sexual reproduction.

2nmeiosis4×n2n \xrightarrow{\text{meiosis}} 4 \times n

Meiosis consists of two successive divisions — Meiosis I and Meiosis II — each with its own prophase, metaphase, anaphase, and telophase.

Meiosis at a Glance

DivisionWhat SeparatesStarting PloidyEnding Ploidy
Meiosis I (reductional)Homologous chromosomes2n2nnn (but chromosomes still double-stranded)
Meiosis II (equational)Sister chromatidsnnnn (single-stranded chromosomes)

After meiosis I, the chromosome number is halved. After meiosis II, the chromatids are separated — the outcome mirrors a mitotic division of a haploid cell.

DNA Replication Before Meiosis

Before meiosis begins, the cell undergoes a normal S phase of interphase — DNA is replicated so that each chromosome now consists of two identical sister chromatids joined at the centromere. This replication is essential; it provides the material for crossing over.

Exam Alert: DNA replication occurs once before meiosis begins, not before each division. There is no S phase between meiosis I and meiosis II. A common exam trap asks which event separates the two phases — the answer is that there is only a brief interkinesis, with no DNA replication.

Meiosis I — Reductional Division

The key distinction of meiosis I is that homologous chromosomes (not sister chromatids) are separated.

Prophase I

This is the longest and most complex phase of meiosis. Several critical events occur:

  1. Chromosomes condense and become visible under a light microscope.
  2. Homologous chromosomes pair up — each pair of homologues comes together in a process called synapsis, forming a bivalent (a tetrad of four chromatids: two from each homologue).
  3. Crossing over occurs — non-sister chromatids of homologous chromosomes exchange corresponding segments of DNA at points called chiasmata (singular: chiasma).
  4. The nuclear envelope breaks down.
  5. Spindle fibres form and begin attaching to centromeres.

Crossing Over — Key Terms

TermDefinition
BivalentA pair of synapsed homologous chromosomes (4 chromatids total)
Chiasma (pl. chiasmata)The physical point where crossing over has occurred between non-sister chromatids
Crossing overThe exchange of corresponding DNA segments between non-sister chromatids of homologous chromosomes
Non-sister chromatidsA chromatid from one homologue paired with a chromatid from the other homologue
Crossing Over at a Chiasma (Prophase I)Before crossing overMaternalchromatidsPaternalchromatidscrossingoverAfter crossing over (chiasma)chiasmarecombinantchromatidMaternal allelesPaternal alleles
Crossing over between non-sister chromatids during Prophase I creates recombinant chromatids with new allele combinations.

Metaphase I

  • Bivalents (pairs of homologous chromosomes) align along the metaphase plate (cell equator).
  • Spindle fibres from opposite poles attach to the centromeres of each homologue in a bivalent.
  • The orientation of each bivalent is random — this is the physical basis of independent assortment.

Anaphase I

  • Homologous chromosomes are pulled to opposite poles by spindle fibres.
  • Sister chromatids remain joined at their centromeres — they do not separate yet.
  • Each pole now has a haploid set of chromosomes, but each chromosome is still double-stranded (two chromatids).

Telophase I and Cytokinesis

  • Nuclear envelopes may reform around each haploid set.
  • Cytokinesis divides the cell into two haploid cells.
  • The cells enter a brief interkinesis — there is no DNA replication.

Meiosis II — Equational Division

Meiosis II is essentially a mitotic division of the two haploid cells produced by meiosis I.

PhaseKey Events
Prophase IIChromosomes recondense; spindle fibres reform; nuclear envelope breaks down
Metaphase IIIndividual chromosomes (each with two chromatids) align at the equator
Anaphase IISister chromatids separate — pulled to opposite poles
Telophase IINuclear envelopes reform; cytokinesis produces four haploid cells

The final result: four haploid cells, each genetically unique.

Sources of Genetic Variation in Meiosis

Meiosis generates genetic variation through three mechanisms:

Three Sources of Variation

  1. Crossing over (Prophase I) — segments of DNA are exchanged between homologous chromosomes, creating new combinations of alleles (recombinant chromosomes). Multiple chiasmata can form per bivalent.

  2. Independent assortment (Metaphase I) — the orientation of each bivalent at the metaphase plate is random and independent of all other bivalents. For an organism with nn chromosome pairs, there are 2n2^n possible chromosome combinations in the gametes. For humans (n=23n = 23): 223=8,388,6082^{23} = 8{,}388{,}608 possible combinations from independent assortment alone.

  3. Random fertilisation — any gamete from one parent can fuse with any gamete from the other parent, multiplying the variation further.

Significance for IB: When an exam question asks about the “significance of meiosis”, the expected answer centres on the generation of genetic variation (through crossing over and independent assortment) and the maintenance of chromosome number across generations (halving chromosome number in gametes so fertilisation restores the diploid number).

Meiosis Stages — Full Summary Diagram

Overview of Meiosis (2n = 4 example)Parent cell2n = 4Meiosis In = 2n = 2Meiosis IIn = 2n = 2n = 2n = 24 haploid cellseach genetically unique(variation from crossing over+ independent assortment)DiploidAfter Meiosis IAfter Meiosis II (haploid)
Meiosis overview: one diploid parent cell produces four genetically unique haploid daughter cells.

Section 2: Inheritance Patterns (D2.2)

Key Terminology

Before working through genetic crosses, master the vocabulary — IB mark schemes are precise about these terms.

Essential Genetics Vocabulary

TermDefinition
GeneA heritable unit of information; a specific sequence of DNA that codes for a polypeptide or functional RNA
AlleleA variant form of a gene, occupying the same locus on homologous chromosomes
LocusThe specific position of a gene on a chromosome
GenotypeThe alleles present in an organism (e.g., AaAa, BBBB)
PhenotypeThe observable/measurable characteristics of an organism
HomozygousBoth alleles at a locus are the same (e.g., AAAA or aaaa)
HeterozygousThe two alleles at a locus differ (e.g., AaAa)
DominantAn allele whose effect is expressed in both heterozygous and homozygous conditions
RecessiveAn allele whose effect is only expressed in the homozygous condition
CodominanceBoth alleles are fully expressed in the heterozygote — both phenotypes are visible simultaneously
Incomplete dominanceThe heterozygote shows an intermediate phenotype between the two homozygotes
CarrierA heterozygous individual who carries a recessive allele but does not express the associated phenotype

Mendel’s Laws

Law of Segregation (Monohybrid Inheritance)

Each individual carries two alleles for each gene. During gamete formation, the two alleles segregate so that each gamete carries only one allele.

This is the basis of monohybrid crosses. Alleles are written as letters: dominant allele as upper case (AA), recessive allele as lower case (aa).

Law of Independent Assortment (Dihybrid Inheritance)

The alleles of two different genes assort into gametes independently of one another, provided the genes are on different (non-homologous) chromosomes.

This is the basis of dihybrid crosses. Note that genes on the same chromosome (linked genes) do not independently assort — this is a key HL concept.

Monohybrid Cross — Worked Example

Example: Pea seed colour (yellow YY dominant over green yy)

Cross: heterozygous yellow (YyYy) × heterozygous yellow (YyYy)

Step 1 — Parental genotypes:

P:Yy×YyP: Yy \times Yy

Step 2 — Gametes produced by each parent:

Parent 1 gametes: YY or yy

Parent 2 gametes: YY or yy

Step 3 — Punnett square:

YYyy
YYYYYYYyYy
yyYyYyyyyy

Step 4 — Genotype ratio: YY:Yy:yy=1:2:1YY : Yy : yy = 1 : 2 : 1

Step 5 — Phenotype ratio: yellow : green = 3:13 : 1

(Both YYYY and YyYy produce yellow phenotype; only yyyy produces green phenotype.)

Testcross

A testcross crosses an individual of unknown genotype with a homozygous recessive individual (aaaa). The ratio of offspring phenotypes reveals the unknown genotype.

Unknown GenotypeCrossOffspring Ratio
Homozygous dominant (AAAA)AA×aaAA \times aaAll dominant phenotype (all AaAa)
Heterozygous (AaAa)Aa×aaAa \times aa1 dominant : 1 recessive (Aa:aaAa : aa)

Exam Alert — Testcross Language: IB mark schemes require you to state the testcross organism is homozygous recessive, not just “recessive”. The distinction matters because the term “recessive” alone could imply heterozygous. Always write: “crossed with a homozygous recessive individual.”

Dihybrid Cross — Worked Example

Example: Pea seed colour (Y/yY/y) and seed shape (RR round dominant over rr wrinkled)

Cross: double heterozygote × double heterozygote (YyRr×YyRrYyRr \times YyRr)

Gametes for each parent (using FOIL or a 4×4 Punnett square):

Each YyRrYyRr parent produces four gamete types: YRYR, YrYr, yRyR, yryr in equal proportions.

Expected phenotype ratio from YyRr×YyRrYyRr \times YyRr:

9 yellow round:3 yellow wrinkled:3 green round:1 green wrinkled9 \text{ yellow round} : 3 \text{ yellow wrinkled} : 3 \text{ green round} : 1 \text{ green wrinkled}

This 9:3:3:1 ratio is the hallmark of a dihybrid cross with two independently assorting genes, each showing simple dominance.

Punnett square (4×4):

YRYRYrYryRyRyryr
YRYRYYRRYYRRYYRrYYRrYyRRYyRRYyRrYyRr
YrYrYYRrYYRrYYrrYYrrYyRrYyRrYyrrYyrr
yRyRYyRRYyRRYyRrYyRryyRRyyRRyyRryyRr
yryrYyRrYyRrYyrrYyrryyRryyRryyrryyrr

Count the phenotypes: 9 with at least one YY and one RR (yellow round), 3 with YY but rrrr (yellow wrinkled), 3 with yyyy but at least one RR (green round), 1 with yyyy and rrrr (green wrinkled).

Codominance — ABO Blood Groups

ABO blood groups are controlled by the II gene with three alleles: IAI^A, IBI^B, and ii.

  • IAI^A and IBI^B are codominant to each other — both alleles are fully expressed
  • ii is recessive to both IAI^A and IBI^B

ABO Blood Group Genotypes and Phenotypes

Phenotype (Blood Type)Possible Genotypes
AIAIAI^A I^A or IAiI^A i
BIBIBI^B I^B or IBiI^B i
ABIAIBI^A I^B (codominance — both A and B antigens present)
Oiiii (homozygous recessive — no A or B antigens)

ABO Cross Example

A mother has blood type A (genotype IAiI^A i) and a father has blood type B (genotype IBiI^B i). What blood types are possible in their children?

Punnett square:

IAI^Aii
IBI^BIAIBI^A I^B (AB)IBiI^B i (B)
iiIAiI^A i (A)iiii (O)

Possible offspring blood types: A, B, AB, and O — all four types are possible (each with probability 1/4).

Incomplete Dominance

In incomplete dominance, the heterozygote shows a phenotype intermediate between the two homozygous phenotypes. Neither allele is dominant or recessive.

Example: Snapdragon flower colour

  • R1R1R^1 R^1 = red flowers
  • R2R2R^2 R^2 = white flowers
  • R1R2R^1 R^2 = pink flowers (intermediate)

Exam Alert — Codominance vs Incomplete Dominance:

  • Codominance: Both allele products are fully expressed — you can detect both simultaneously (e.g., type AB blood has both A and B antigens; a roan cow has both red and white hairs)
  • Incomplete dominance: The heterozygote shows a blend/intermediate phenotype not seen in either homozygote (e.g., pink snapdragons from red × white cross)

These are frequently confused on Paper 1. The key question is: “Can you detect both original phenotypes in the heterozygote?” If yes → codominance. If no, and you see a blend → incomplete dominance.

Sex-Linked Inheritance (X-linked Traits)

In humans, the sex chromosomes are XX (larger, gene-rich) and YY (smaller, fewer genes). Genes located on the X chromosome but not on the Y chromosome are called X-linked (or sex-linked).

Because males have only one X chromosome (hemizygous), they express X-linked recessive traits whenever the allele is present on their single X chromosome — there is no second X to “mask” a recessive allele.

Notation for X-linked genes:

  • XHX^H = dominant allele (e.g., normal blood clotting)
  • XhX^h = recessive allele (e.g., haemophilia)
  • XHXHX^H X^H = homozygous dominant female (normal)
  • XHXhX^H X^h = heterozygous carrier female (normal phenotype, carries recessive allele)
  • XhXhX^h X^h = affected female (recessive phenotype)
  • XHYX^H Y = normal male
  • XhYX^h Y = affected male (hemizygous — only one X allele)

X-linked Haemophilia Cross

A carrier female (XHXhX^H X^h) × normal male (XHYX^H Y)

Gametes: Female produces XHX^H and XhX^h; Male produces XHX^H and YY

Punnett square:

XHX^HXhX^h
XHX^HXHXHX^H X^H (normal female)XHXhX^H X^h (carrier female)
YYXHYX^H Y (normal male)XhYX^h Y (haemophiliac male)

Phenotype ratio: 1 normal female : 1 carrier female : 1 normal male : 1 haemophiliac male

Key point: 1/2 of all sons will be affected; 0 daughters will be affected (but 1/2 will be carriers). Haemophilia is more common in males because males only need one copy of the recessive allele.

IB Exam Language for Sex-linkage: When asked to explain why X-linked recessive conditions are more common in males, the expected answer is: males are hemizygous for X-linked genes — they have only one copy of the X chromosome and therefore express any allele on it, whether dominant or recessive. Do not simply write “boys only have one X chromosome” without explaining the hemizygous consequence.

Pedigree Analysis

IB often presents a pedigree chart (family tree diagram) and asks you to determine the mode of inheritance.

Pedigree Clues — Mode of Inheritance

ObservationLikely Conclusion
Trait skips generationsRecessive
All affected individuals have at least one affected parentDominant
More affected males than femalesX-linked recessive
Affected father has all affected daughters, no affected sonsX-linked dominant
Unaffected parents have affected childRecessive (both parents are carriers)
Male-to-male transmission presentAutosomal (NOT X-linked — Y is required for male-to-male)

Section 3: Gene Pools & Speciation (D2.3) HL

Gene Pools and Allele Frequency

A gene pool is the total set of all alleles of all genes present in a population at a given time.

Allele frequency is the proportion of a particular allele among all alleles of that gene in the population.

Allele frequency of A=number of A allelestotal number of alleles for that gene in population\text{Allele frequency of } A = \frac{\text{number of } A \text{ alleles}}{\text{total number of alleles for that gene in population}}

Example: In a population of 100 diploid individuals, if 60 carry the AA allele out of 200 total alleles: allele frequency of A=60200=0.30A = \frac{60}{200} = 0.30

Hardy-Weinberg Principle (Qualitative)

The Hardy-Weinberg principle states that allele and genotype frequencies in a population remain constant from generation to generation in the absence of evolutionary influences.

Hardy-Weinberg Equilibrium Conditions (MARGE)

A population is in Hardy-Weinberg equilibrium only if all of the following conditions are met:

  1. Mating is random (no sexual selection)
  2. Allele frequencies are not altered by mutation
  3. Random genetic drift is negligible (population is very large)
  4. Gene flow does not occur (no migration in or out)
  5. Evolution is not occurring (no natural selection)

Real populations virtually never meet all five conditions, so Hardy-Weinberg equilibrium is a theoretical baseline.

IB Requirement for D2.3: The IB 2025 syllabus requires a qualitative understanding of Hardy-Weinberg — you should know what the principle states and what conditions are required, but you are not required to perform calculations using the Hardy-Weinberg equations (p+q=1p + q = 1; p2+2pq+q2=1p^2 + 2pq + q^2 = 1) at SL. HL students should be aware of the equations and what each term represents, but the primary exam demand is explaining the conditions and significance.

Speciation

Speciation is the evolutionary process by which new species arise. A species is a group of organisms that share common characteristics and can interbreed to produce fertile offspring.

Reproductive isolation is the key mechanism — once populations can no longer exchange genes, they diverge.

Allopatric Speciation

Allopatric speciation occurs when a population is divided by a geographical barrier (mountain range, ocean, river), creating two isolated sub-populations.

Process:

  1. Original population is split by a geographic barrier.
  2. Gene flow between populations ceases.
  3. Each sub-population is subject to different selection pressures, mutations, and genetic drift.
  4. Over time, allele frequencies diverge.
  5. Populations accumulate enough genetic differences that, if brought back together, they can no longer interbreed → reproductive isolation is complete → two species.

Example: Darwin’s finches on the Galápagos Islands — ancestral finches colonised different islands; geographical isolation led to divergence in beak morphology and feeding behaviour.

Sympatric Speciation

Sympatric speciation occurs within the same geographical area — no physical barrier separates the populations. It is less common in animals but well-documented in plants and insects.

Mechanisms include:

  • Polyploidy — a sudden multiplication of chromosome sets (common in plants). An allopolyploid organism (with chromosome sets from two different species) cannot reproduce with either parent species → instant speciation.
  • Ecological specialisation — subpopulations exploit different resources in the same area, reducing gene flow between them (e.g., insects specialising on different host plants).

Example: Many crop plants (wheat, cotton) arose through allopolyploidy.

FeatureAllopatric SpeciationSympatric Speciation
Geographic barrierRequiredNot required
Gene flow interrupted byPhysical separationReproductive/ecological isolation
Common inAnimals and plantsPrimarily plants (polyploidy); some insects
SpeedGradual (thousands of generations)Can be rapid (polyploidy can be near-instantaneous)

Exam Alert — Speciation Definitions: IB mark schemes award marks for precision. “Allopatric” = geographic isolation. “Sympatric” = same area, no geographic barrier. Simply writing “isolation” without the qualifier will lose marks. Always specify the type of isolation.


Section 4: MCQ Practice (IB Paper 1 Style)

Question 1. Which of the following events occurs during prophase I of meiosis but NOT during prophase of mitosis?

A. Chromosomes condense and become visible.

B. The nuclear envelope breaks down.

C. Homologous chromosomes pair and crossing over occurs.

D. Spindle fibres begin to form.

Reveal answer

C — Synapsis (pairing of homologous chromosomes) and crossing over at chiasmata are exclusive to prophase I of meiosis. Options A, B, and D occur in both prophase I of meiosis and prophase of mitosis.


Question 2. In a population of rabbits, the allele for brown coat (BB) is dominant over the allele for white coat (bb). Two brown rabbits are crossed and produce 3 brown offspring and 1 white offspring. What are the genotypes of the parent rabbits?

A. BB×BBBB \times BB

B. BB×BbBB \times Bb

C. Bb×BbBb \times Bb

D. Bb×bbBb \times bb

Reveal answer

C — A 3:1 phenotype ratio (3 brown : 1 white) is the hallmark of a cross between two heterozygotes (Bb×BbBb \times Bb). The offspring genotypes are 1 BBBB : 2 BbBb : 1 bbbb, giving the 3 brown : 1 white phenotype ratio. Option D (Bb×bbBb \times bb) would give a 1:1 ratio; option B (BB×BbBB \times Bb) would give all brown (no white offspring possible).


Question 3. A woman with type AB blood and a man with type O blood have children. Which of the following blood types is POSSIBLE for their children?

A. Type O

B. Type AB

C. Type A

D. Neither A nor B can be produced

Reveal answer

C — The mother with type AB has genotype IAIBI^A I^B. The father with type O has genotype iiii. Possible gametes: mother produces IAI^A and IBI^B; father produces only ii. Offspring genotypes: IAiI^A i (type A) and IBiI^B i (type B). Type A and Type B are both possible. Type O (requiring iiii) and Type AB (requiring IAIBI^A I^B) cannot be produced. The answer is C (Type A is possible).


Question 4. Haemophilia is an X-linked recessive condition. A non-haemophiliac woman whose father had haemophilia marries a non-haemophiliac man. What is the probability that their first son will have haemophilia?

A. 0 (impossible)

B. 1/4

C. 1/2

D. 1 (certain)

Reveal answer

C — The woman’s father had haemophilia (XhYX^h Y), so she must have received XhX^h from him. Since she is unaffected, she is a carrier (XHXhX^H X^h). Her husband is normal (XHYX^H Y). The cross XHXh×XHYX^H X^h \times X^H Y produces XHXHX^H X^H, XHXhX^H X^h, XHYX^H Y, XhYX^h Y in equal proportions. Among sons, half will be XHYX^H Y (normal) and half will be XhYX^h Y (haemophiliac). The probability that their first son has haemophilia is 1/2.


Question 5. Which of the following is NOT a condition required for a population to be in Hardy-Weinberg equilibrium?

A. No migration into or out of the population

B. Random mating within the population

C. Large population size

D. High rate of mutation at the gene locus in question

Reveal answer

D — A high mutation rate would alter allele frequencies, violating Hardy-Weinberg equilibrium. Hardy-Weinberg requires the absence of mutation (or at least mutation rates so low they do not measurably alter allele frequencies). Options A, B, and C (no migration, random mating, large population size) are all required conditions for equilibrium.


Question 6. A new species of plant arose when a hybrid formed between two different species underwent chromosome doubling (polyploidy). This is an example of which type of speciation?

A. Allopatric speciation due to geographic isolation

B. Allopatric speciation due to reproductive isolation

C. Sympatric speciation

D. Adaptive radiation

Reveal answer

C — Polyploidy-driven speciation occurs without geographic separation — the new species arises within the same area as both parent species. This is the definition of sympatric speciation. Allopatric speciation (A, B) requires a geographic barrier. Adaptive radiation (D) refers to rapid diversification of one ancestral species into many niches, which is a pattern — not a mechanism of speciation.


Quick Recall — All Sections

Try to answer without scrolling up:

  1. What separates during anaphase I of meiosis versus anaphase II?
  2. What is the phenotype ratio expected from a monohybrid cross of two heterozygotes?
  3. Why are X-linked recessive conditions more common in males than females?
  4. Name the two types of speciation and their key distinguishing feature.
  5. State two conditions required for Hardy-Weinberg equilibrium.
Reveal answers
  1. Anaphase I: homologous chromosomes separate (sister chromatids remain joined). Anaphase II: sister chromatids separate (same as mitotic anaphase).
  2. 3:1 (3 dominant phenotype : 1 recessive phenotype).
  3. Males are hemizygous for X-linked genes — they have only one X chromosome and will express any allele (dominant or recessive) present on it. There is no second X allele to mask a recessive allele.
  4. Allopatric — populations separated by a geographic barrier; Sympatric — speciation within the same geographic area (no physical barrier), typically via polyploidy or ecological specialisation.
  5. Any two from: random mating, no mutation, large population size (no genetic drift), no migration (no gene flow), no natural selection.

Section 5: Exam Strategy

Top Mistakes on D2 Questions

  1. Confusing what separates in meiosis I vs meiosis II. In meiosis I: homologous chromosomes separate. In meiosis II: sister chromatids separate. A diagram question showing double-stranded chromosomes moving apart = meiosis I. Single-stranded = meiosis II or mitosis.

  2. Forgetting to show all gamete types in a dihybrid cross. For AaBbAaBb parents, there are four gamete types (ABAB, AbAb, aBaB, abab). Students often write only two gametes. In a 4×4 Punnett square, you must list all four.

  3. Writing “dominant” instead of “codominant” for ABO blood groups. IAI^A is not dominant over IBI^B — they are codominant. Saying ”IAI^A is dominant and IBI^B is recessive” is factually incorrect.

  4. Confusing incomplete dominance with codominance. Use the test: can you detect both original phenotypes in the heterozygote? If yes (e.g., roan cattle have both red and white hairs) → codominance. If the heterozygote is a blend (e.g., pink snapdragons) → incomplete dominance.

  5. Failing to use notation correctly for X-linked alleles. Always write X-linked alleles as superscripts on X: XHX^H and XhX^h, not simply HH or hh. The IB mark scheme requires the X to appear in the genotype.

  6. Confusing allopatric and sympatric speciation. “Allopatric” = geo (geographic) separation. “Sympatric” = same place, reproductive/ecological isolation.

Genetic Cross Method for IB Exams:

Always show your working in four explicit steps:

  1. State parental genotypes
  2. State gametes for each parent
  3. Complete the Punnett square
  4. State genotype ratio then phenotype ratio

The IB mark scheme awards marks at each step. Even if your final ratio is wrong due to a counting error, you can earn marks for correctly stating gametes and setting up the Punnett square.

Fast-Recall Checklist — D2 Key Facts

  • Meiosis I separates homologous chromosomes (2nn2n \rightarrow n); Meiosis II separates sister chromatids (nnn \rightarrow n)
  • Crossing over: exchange of DNA between non-sister chromatids of homologous chromosomes at chiasmata in prophase I
  • Independent assortment: random orientation of bivalents at metaphase I
  • Monohybrid Aa × Aa → 3:1 phenotype ratio
  • Dihybrid AaBb × AaBb → 9:3:3:1 phenotype ratio
  • ABO: IAI^A and IBI^B codominant; ii recessive to both
  • X-linked recessive: males more commonly affected (hemizygous)
  • Testcross: unknown genotype × homozygous recessive
  • Hardy-Weinberg: stable allele frequencies require no mutation, random mating, large population, no migration, no selection
  • Allopatric speciation: geographic barrier; Sympatric speciation: same area (polyploidy/ecological)

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